[SQL] 리트코드 197. Rising Temperature

문제

Table: Weather

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+

id is the column with unique values for this table.
This table contains information about the temperature on a certain day.

 

Write a solution to find all dates' Id with higher temperatures compared to its previous dates (yesterday).
Return the result table in any order.
The result format is in the following example.

 

https://leetcode.com/problems/rising-temperature/description/

Rising Temperature - LeetCode

예시

Example 1:
Input: 
Weather table:

+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+

Output: 

+----+
| id |
+----+
| 2  |
| 4  |
+----+

Explanation: 
In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
In 2015-01-04, the temperature was higher than the previous day (20 -> 30).

문제 풀이

SELECT Today.id
FROM Weather AS Today
INNER JOIN Weather AS Yesterday ON DATE_ADD(Yesterday.recordDate, INTERVAL 1 DAY) = Today.recordDate
WHERE Today.temperature > Yesterday.temperature

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SQL을 독학하시는 분들에게 도움이 되길 바라며,

혹 더 좋은 방법이 있거나 오류가 있다면 편하게 말씀 부탁드립니다.